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(-3x)+(x^2)+2.5=0
determiningTheFunctionDomain x^2+(-3x)+2.5=0
We get rid of parentheses
x^2-3x+2.5=0
a = 1; b = -3; c = +2.5;
Δ = b2-4ac
Δ = -32-4·1·2.5
Δ = -1
Delta is less than zero, so there is no solution for the equation
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